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102130014151 = 1159464333893
BaseRepresentation
bin101111100011101101…
…1000101011111000111
3100202121121122021100201
41133013123011133013
53133130240423101
6114530132351331
710243606540204
oct1370733053707
9322547567321
10102130014151
113a349804280
1217963175547
139827ba8b49
144d2bcc0cab
1529cb22ee01
hex17c76c57c7

102130014151 has 16 divisors (see below), whose sum is σ = 113330689920. Its totient is φ = 91249465120.

The previous prime is 102130014149. The next prime is 102130014167. The reversal of 102130014151 is 151410031201.

It is not a de Polignac number, because 102130014151 - 21 = 102130014149 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (102130014451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2996361 + ... + 3030253.

It is an arithmetic number, because the mean of its divisors is an integer number (7083168120).

Almost surely, 2102130014151 is an apocalyptic number.

102130014151 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

102130014151 is a deficient number, since it is larger than the sum of its proper divisors (11200675769).

102130014151 is a wasteful number, since it uses less digits than its factorization.

102130014151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38606.

The product of its (nonzero) digits is 120, while the sum is 19.

Adding to 102130014151 its reverse (151410031201), we get a palindrome (253540045352).

The spelling of 102130014151 in words is "one hundred two billion, one hundred thirty million, fourteen thousand, one hundred fifty-one".

Divisors: 1 11 59 649 4643 33893 51073 273937 372823 1999687 3013307 21996557 157365199 1731017189 9284546741 102130014151