Search a number
-
+
10213001423031 = 311309484891607
BaseRepresentation
bin1001010010011110011001…
…0100100110100010110111
31100011100112121222122211010
42110213212110212202313
52314312211331014111
633415442120443303
72102602460513601
oct224474624464267
940140477878733
1010213001423031
113288345061830
12118b421619533
1359110ac27004
14274451c2a171
1512a9e49eaaa6
hex949e65268b7

10213001423031 has 8 divisors (see below), whose sum is σ = 14855274797184. Its totient is φ = 6189697832120.

The previous prime is 10213001423011. The next prime is 10213001423039. The reversal of 10213001423031 is 13032410031201.

10213001423031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-10213001423031 is a prime.

It is a super-2 number, since 2×102130014230312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10213001422989 and 10213001423007.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10213001423039) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 154742445771 + ... + 154742445836.

It is an arithmetic number, because the mean of its divisors is an integer number (1856909349648).

Almost surely, 210213001423031 is an apocalyptic number.

10213001423031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

10213001423031 is a deficient number, since it is larger than the sum of its proper divisors (4642273374153).

10213001423031 is a wasteful number, since it uses less digits than its factorization.

10213001423031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 309484891621.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 10213001423031 its reverse (13032410031201), we get a palindrome (23245411454232).

The spelling of 10213001423031 in words is "ten trillion, two hundred thirteen billion, one million, four hundred twenty-three thousand, thirty-one".

Divisors: 1 3 11 33 309484891607 928454674821 3404333807677 10213001423031