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102131001330000 = 2435431109818281
BaseRepresentation
bin10111001110001100111010…
…000011100000100101010000
3111101121121222002021110101220
4113032030322003200211100
5101341303242320030000
61001114200112525040
730340502264445156
oct2716147203404520
9441547862243356
10102131001330000
112a5a6572779145
12b555809850780
1344cabb1b664a6
141b31249b433d6
15bc19dd4a61a0
hex5ce33a0e0950

102131001330000 has 200 divisors, whose sum is σ = 340327734464256. Its totient is φ = 26356387200000.

The previous prime is 102131001329993. The next prime is 102131001330109. The reversal of 102131001330000 is 33100131201.

It is a tau number, because it is divible by the number of its divisors (200).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 53979141 + ... + 55839140.

Almost surely, 2102131001330000 is an apocalyptic number.

102131001330000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

102131001330000 is an abundant number, since it is smaller than the sum of its proper divisors (238196733134256).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

102131001330000 is a wasteful number, since it uses less digits than its factorization.

102131001330000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 109818343 (or 109818322 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 102131001330000 its reverse (33100131201), we get a palindrome (102164101461201).

The spelling of 102131001330000 in words is "one hundred two trillion, one hundred thirty-one billion, one million, three hundred thirty thousand".