Base | Representation |
---|---|
bin | 11101101110010101101… |
… | …00111100000100110111 |
3 | 10121122011212011220110121 |
4 | 32313022310330010313 |
5 | 113213120342434333 |
6 | 2101103340232411 |
7 | 133534005551305 |
oct | 16671264740467 |
9 | 3548155156417 |
10 | 1021310124343 |
11 | 364153a37803 |
12 | 145b2a83b707 |
13 | 75403214782 |
14 | 37608727275 |
15 | 1b87752232d |
hex | edcad3c137 |
1021310124343 has 2 divisors, whose sum is σ = 1021310124344. Its totient is φ = 1021310124342.
The previous prime is 1021310124283. The next prime is 1021310124371. The reversal of 1021310124343 is 3434210131201.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1021310124343 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1021310124383) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510655062171 + 510655062172.
It is an arithmetic number, because the mean of its divisors is an integer number (510655062172).
Almost surely, 21021310124343 is an apocalyptic number.
1021310124343 is a deficient number, since it is larger than the sum of its proper divisors (1).
1021310124343 is an equidigital number, since it uses as much as digits as its factorization.
1021310124343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1021310124343 its reverse (3434210131201), we get a palindrome (4455520255544).
The spelling of 1021310124343 in words is "one trillion, twenty-one billion, three hundred ten million, one hundred twenty-four thousand, three hundred forty-three".
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