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10213140000 = 25354724317
BaseRepresentation
bin10011000001100000…
…00010011000100000
3222100202211021020110
421200300002120200
5131404030440000
64405235011320
7511043154240
oct114060023040
928322737213
1010213140000
114371062278
121b90439b40
13c69bc560b
146cc5a5b20
153eb960850
hex260c02620

10213140000 has 240 divisors, whose sum is σ = 38288593728. Its totient is φ = 2334336000.

The previous prime is 10213139891. The next prime is 10213140001. The reversal of 10213140000 is 4131201.

It is a happy number.

It is a tau number, because it is divible by the number of its divisors (240).

It is a Harshad number since it is a multiple of its sum of digits (12).

It is not an unprimeable number, because it can be changed into a prime (10213140001) by changing a digit.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 407842 + ... + 432158.

Almost surely, 210213140000 is an apocalyptic number.

10213140000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 10213140000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19144296864).

10213140000 is an abundant number, since it is smaller than the sum of its proper divisors (28075453728).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10213140000 is an equidigital number, since it uses as much as digits as its factorization.

10213140000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24357 (or 24334 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 12.

Adding to 10213140000 its reverse (4131201), we get a palindrome (10217271201).

The spelling of 10213140000 in words is "ten billion, two hundred thirteen million, one hundred forty thousand".