Base | Representation |
---|---|
bin | 10011000001100000… |
… | …10011101111001001 |
3 | 222100202221212202002 |
4 | 21200300103233021 |
5 | 131404040223311 |
6 | 4405240320345 |
7 | 511043601413 |
oct | 114060235711 |
9 | 28322855662 |
10 | 10213211081 |
11 | 4371100717 |
12 | 1b904730b5 |
13 | c69c1ba88 |
14 | 6cc5c39b3 |
15 | 3eb97693b |
hex | 260c13bc9 |
10213211081 has 2 divisors, whose sum is σ = 10213211082. Its totient is φ = 10213211080.
The previous prime is 10213211011. The next prime is 10213211083. The reversal of 10213211081 is 18011231201.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9572665600 + 640545481 = 97840^2 + 25309^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10213211081 is a prime.
It is a super-3 number, since 3×102132110813 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 10213211083, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (10213211083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106605540 + 5106605541.
It is an arithmetic number, because the mean of its divisors is an integer number (5106605541).
Almost surely, 210213211081 is an apocalyptic number.
It is an amenable number.
10213211081 is a deficient number, since it is larger than the sum of its proper divisors (1).
10213211081 is an equidigital number, since it uses as much as digits as its factorization.
10213211081 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 20.
Adding to 10213211081 its reverse (18011231201), we get a palindrome (28224442282).
The spelling of 10213211081 in words is "ten billion, two hundred thirteen million, two hundred eleven thousand, eighty-one".
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