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10213301103 = 33793897557
BaseRepresentation
bin10011000001100001…
…01001101101101111
3222100210010110020020
421200300221231233
5131404101113403
64405242253223
7511044425025
oct114060515557
928323113206
1010213301103
114371162315
121b904b7213
13c69c50a45
146cc608715
153eb993453
hex260c29b6f

10213301103 has 8 divisors (see below), whose sum is σ = 13621340208. Its totient is φ = 6807064704.

The previous prime is 10213301101. The next prime is 10213301149. The reversal of 10213301103 is 30110331201.

10213301103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 10213301103 - 21 = 10213301101 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10213301101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 437400 + ... + 460157.

It is an arithmetic number, because the mean of its divisors is an integer number (1702667526).

Almost surely, 210213301103 is an apocalyptic number.

10213301103 is a deficient number, since it is larger than the sum of its proper divisors (3408039105).

10213301103 is an equidigital number, since it uses as much as digits as its factorization.

10213301103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 901353.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 10213301103 its reverse (30110331201), we get a palindrome (40323632304).

The spelling of 10213301103 in words is "ten billion, two hundred thirteen million, three hundred one thousand, one hundred three".

Divisors: 1 3 3793 11379 897557 2692671 3404433701 10213301103