Base | Representation |
---|---|
bin | 10011000001101000… |
… | …10010011101110011 |
3 | 222100211220212222102 |
4 | 21200310102131303 |
5 | 131404322120301 |
6 | 4405314531015 |
7 | 511055505332 |
oct | 114064223563 |
9 | 28324825872 |
10 | 10214254451 |
11 | 4371753605 |
12 | 1b90896a6b |
13 | c6a1c595b |
14 | 6cc7b5d19 |
15 | 3ebad0b6b |
hex | 260d12773 |
10214254451 has 2 divisors, whose sum is σ = 10214254452. Its totient is φ = 10214254450.
The previous prime is 10214254433. The next prime is 10214254487. The reversal of 10214254451 is 15445241201.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10214254451 - 218 = 10213992307 is a prime.
It is a super-2 number, since 2×102142544512 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10214254411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5107127225 + 5107127226.
It is an arithmetic number, because the mean of its divisors is an integer number (5107127226).
Almost surely, 210214254451 is an apocalyptic number.
10214254451 is a deficient number, since it is larger than the sum of its proper divisors (1).
10214254451 is an equidigital number, since it uses as much as digits as its factorization.
10214254451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6400, while the sum is 29.
Adding to 10214254451 its reverse (15445241201), we get a palindrome (25659495652).
The spelling of 10214254451 in words is "ten billion, two hundred fourteen million, two hundred fifty-four thousand, four hundred fifty-one".
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