Base | Representation |
---|---|
bin | 10111001111001101010111… |
… | …010101010000110101101111 |
3 | 111101212020121111100210020011 |
4 | 113033031113111100311233 |
5 | 101343422013233000421 |
6 | 1001210043525434051 |
7 | 30345502345441411 |
oct | 2717152725206557 |
9 | 441766544323204 |
10 | 102200212000111 |
11 | 2a622959357a65 |
12 | b56710426b927 |
13 | 45045918c5824 |
14 | 1b347339aa9b1 |
15 | bc36de64b4e1 |
hex | 5cf357550d6f |
102200212000111 has 2 divisors, whose sum is σ = 102200212000112. Its totient is φ = 102200212000110.
The previous prime is 102200212000057. The next prime is 102200212000163. The reversal of 102200212000111 is 111000212002201.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 102200212000111 - 211 = 102200211998063 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 102200212000091 and 102200212000100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (102200212000181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51100106000055 + 51100106000056.
It is an arithmetic number, because the mean of its divisors is an integer number (51100106000056).
Almost surely, 2102200212000111 is an apocalyptic number.
102200212000111 is a deficient number, since it is larger than the sum of its proper divisors (1).
102200212000111 is an equidigital number, since it uses as much as digits as its factorization.
102200212000111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 102200212000111 its reverse (111000212002201), we get a palindrome (213200424002312).
The spelling of 102200212000111 in words is "one hundred two trillion, two hundred billion, two hundred twelve million, one hundred eleven", and thus it is an aban number.
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