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10220130013 = 731055913259
BaseRepresentation
bin10011000010010101…
…01100111011011101
3222101020222101201211
421201022230323131
5131412323130023
64410044504421
7511156446262
oct114112547335
928336871654
1010220130013
114374aa6a45
121b9284b111
13c6b4a2112
146cd4a5269
153ec391a0d
hex2612acedd

10220130013 has 8 divisors (see below), whose sum is σ = 10361894400. Its totient is φ = 10078413408.

The previous prime is 10220130007. The next prime is 10220130031. The reversal of 10220130013 is 31003102201.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10220130013 - 25 = 10220129981 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10220129975 and 10220130002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10220130113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 764178 + ... + 777436.

It is an arithmetic number, because the mean of its divisors is an integer number (1295236800).

Almost surely, 210220130013 is an apocalyptic number.

It is an amenable number.

10220130013 is a deficient number, since it is larger than the sum of its proper divisors (141764387).

10220130013 is a wasteful number, since it uses less digits than its factorization.

10220130013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23891.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 10220130013 its reverse (31003102201), we get a palindrome (41223232214).

The spelling of 10220130013 in words is "ten billion, two hundred twenty million, one hundred thirty thousand, thirteen".

Divisors: 1 73 10559 13259 770807 967907 140001781 10220130013