Search a number
-
+
102201502211 is a prime number
BaseRepresentation
bin101111100101110101…
…1110010101000000011
3100202210121011020112122
41133023223302220003
53133302041032321
6114541204514455
710245435302204
oct1371353625003
9322717136478
10102201502211
113a3860a1316
12179830aba2b
139839948a83
144d375ad5ab
1529d26518ab
hex17cbaf2a03

102201502211 has 2 divisors, whose sum is σ = 102201502212. Its totient is φ = 102201502210.

The previous prime is 102201502177. The next prime is 102201502213. The reversal of 102201502211 is 112205102201.

It is a strong prime.

It is an emirp because it is prime and its reverse (112205102201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 102201502211 - 222 = 102197307907 is a prime.

Together with 102201502213, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 102201502211.

It is not a weakly prime, because it can be changed into another prime (102201502213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51100751105 + 51100751106.

It is an arithmetic number, because the mean of its divisors is an integer number (51100751106).

Almost surely, 2102201502211 is an apocalyptic number.

102201502211 is a deficient number, since it is larger than the sum of its proper divisors (1).

102201502211 is an equidigital number, since it uses as much as digits as its factorization.

102201502211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 80, while the sum is 17.

Adding to 102201502211 its reverse (112205102201), we get a palindrome (214406604412).

The spelling of 102201502211 in words is "one hundred two billion, two hundred one million, five hundred two thousand, two hundred eleven".