Base | Representation |
---|---|
bin | 10111001111001111001001… |
… | …000011101101001000000011 |
3 | 111101212102112110121020000211 |
4 | 113033033021003231020003 |
5 | 101343434420210000003 |
6 | 1001211001124454551 |
7 | 30345600544250332 |
oct | 2717171103551003 |
9 | 441772473536024 |
10 | 102202120000003 |
11 | 2a623748377581 |
12 | b56755724a457 |
13 | 4504806c9a74a |
14 | 1b34875157d19 |
15 | bc37a1dd996d |
hex | 5cf3c90ed203 |
102202120000003 has 2 divisors, whose sum is σ = 102202120000004. Its totient is φ = 102202120000002.
The previous prime is 102202119999913. The next prime is 102202120000091. The reversal of 102202120000003 is 300000021202201.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 102202120000003 - 241 = 100003096744451 is a prime.
It is not a weakly prime, because it can be changed into another prime (102202120000403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51101060000001 + 51101060000002.
It is an arithmetic number, because the mean of its divisors is an integer number (51101060000002).
Almost surely, 2102202120000003 is an apocalyptic number.
102202120000003 is a deficient number, since it is larger than the sum of its proper divisors (1).
102202120000003 is an equidigital number, since it uses as much as digits as its factorization.
102202120000003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 13.
Adding to 102202120000003 its reverse (300000021202201), we get a palindrome (402202141202204).
The spelling of 102202120000003 in words is "one hundred two trillion, two hundred two billion, one hundred twenty million, three", and thus it is an aban number.
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