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1022113433 = 1199793199
BaseRepresentation
bin111100111011000…
…011011010011001
32122020021202001002
4330323003122121
54043130112213
6245231234345
734220551355
oct7473033231
92566252032
101022113433
11484a57a50
122463789b5
131339b0563
1499a66465
155eaed658
hex3cec3699

1022113433 has 8 divisors (see below), whose sum is σ = 1116163200. Its totient is φ = 928252080.

The previous prime is 1022113409. The next prime is 1022113441. The reversal of 1022113433 is 3343112201.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1022113433 - 210 = 1022112409 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1022113403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35633 + ... + 57566.

It is an arithmetic number, because the mean of its divisors is an integer number (139520400).

Almost surely, 21022113433 is an apocalyptic number.

It is an amenable number.

1022113433 is a deficient number, since it is larger than the sum of its proper divisors (94049767).

1022113433 is an equidigital number, since it uses as much as digits as its factorization.

1022113433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 94207.

The product of its (nonzero) digits is 432, while the sum is 20.

The square root of 1022113433 is about 31970.5088010810. The cubic root of 1022113433 is about 1007.3174683843.

Adding to 1022113433 its reverse (3343112201), we get a palindrome (4365225634).

The spelling of 1022113433 in words is "one billion, twenty-two million, one hundred thirteen thousand, four hundred thirty-three".

Divisors: 1 11 997 10967 93199 1025189 92919403 1022113433