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102231299173 is a prime number
BaseRepresentation
bin101111100110101110…
…1011101010001100101
3100202212200020002021211
41133031131131101211
53133332203033143
6114544151311421
710246246463623
oct1371535352145
9322780202254
10102231299173
113a3a09a3203
121799107b571
139842b7c503
144d3b528513
1529d508a49d
hex17cd75d465

102231299173 has 2 divisors, whose sum is σ = 102231299174. Its totient is φ = 102231299172.

The previous prime is 102231299171. The next prime is 102231299249. The reversal of 102231299173 is 371992132201.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 88032670209 + 14198628964 = 296703^2 + 119158^2 .

It is an emirp because it is prime and its reverse (371992132201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 102231299173 - 21 = 102231299171 is a prime.

Together with 102231299171, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (102231299171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51115649586 + 51115649587.

It is an arithmetic number, because the mean of its divisors is an integer number (51115649587).

Almost surely, 2102231299173 is an apocalyptic number.

It is an amenable number.

102231299173 is a deficient number, since it is larger than the sum of its proper divisors (1).

102231299173 is an equidigital number, since it uses as much as digits as its factorization.

102231299173 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40824, while the sum is 40.

The spelling of 102231299173 in words is "one hundred two billion, two hundred thirty-one million, two hundred ninety-nine thousand, one hundred seventy-three".