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102232211320037 is a prime number
BaseRepresentation
bin10111001111101011001010…
…101000111110110011100101
3111101222022012120201122221102
4113033223022220332303211
5101344433032044220122
61001232455102125445
730351014333250341
oct2717531250766345
9441868176648842
10102232211320037
112a63548a113707
12b571354880885
1345075c1257566
141b360cb774621
15bc4463a51492
hex5cfacaa3ece5

102232211320037 has 2 divisors, whose sum is σ = 102232211320038. Its totient is φ = 102232211320036.

The previous prime is 102232211319961. The next prime is 102232211320051. The reversal of 102232211320037 is 730023112232201.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 82668937324516 + 19563273995521 = 9092246^2 + 4423039^2 .

It is a cyclic number.

It is not a de Polignac number, because 102232211320037 - 28 = 102232211319781 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 102232211319991 and 102232211320009.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (102232211320087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51116105660018 + 51116105660019.

It is an arithmetic number, because the mean of its divisors is an integer number (51116105660019).

Almost surely, 2102232211320037 is an apocalyptic number.

It is an amenable number.

102232211320037 is a deficient number, since it is larger than the sum of its proper divisors (1).

102232211320037 is an equidigital number, since it uses as much as digits as its factorization.

102232211320037 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048, while the sum is 29.

Adding to 102232211320037 its reverse (730023112232201), we get a palindrome (832255323552238).

The spelling of 102232211320037 in words is "one hundred two trillion, two hundred thirty-two billion, two hundred eleven million, three hundred twenty thousand, thirty-seven".