Base | Representation |
---|---|
bin | 10111001111101011001010… |
… | …101000111110110100010111 |
3 | 111101222022012120201200000021 |
4 | 113033223022220332310113 |
5 | 101344433032044220322 |
6 | 1001232455102130011 |
7 | 30351014333250442 |
oct | 2717531250766427 |
9 | 441868176650007 |
10 | 102232211320087 |
11 | 2a63548a113752 |
12 | b571354880907 |
13 | 45075c12575a4 |
14 | 1b360cb774659 |
15 | bc4463a514c7 |
hex | 5cfacaa3ed17 |
102232211320087 has 2 divisors, whose sum is σ = 102232211320088. Its totient is φ = 102232211320086.
The previous prime is 102232211320051. The next prime is 102232211320111. The reversal of 102232211320087 is 780023112232201.
It is a strong prime.
It is an emirp because it is prime and its reverse (780023112232201) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 102232211320087 - 215 = 102232211287319 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (102232211320037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51116105660043 + 51116105660044.
It is an arithmetic number, because the mean of its divisors is an integer number (51116105660044).
Almost surely, 2102232211320087 is an apocalyptic number.
102232211320087 is a deficient number, since it is larger than the sum of its proper divisors (1).
102232211320087 is an equidigital number, since it uses as much as digits as its factorization.
102232211320087 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 34.
Adding to 102232211320087 its reverse (780023112232201), we get a palindrome (882255323552288).
The spelling of 102232211320087 in words is "one hundred two trillion, two hundred thirty-two billion, two hundred eleven million, three hundred twenty thousand, eighty-seven".
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