Base | Representation |
---|---|
bin | 10111010000101110010100… |
… | …001011010000111101110111 |
3 | 111102020012022101212221010012 |
4 | 113100232110023100331313 |
5 | 101402123212333120341 |
6 | 1001325541354050435 |
7 | 30356146136044403 |
oct | 2720562413207567 |
9 | 442205271787105 |
10 | 102304312004471 |
11 | 2a663019071015 |
12 | b583317119a1b |
13 | 451134196c445 |
14 | 1b397ab374103 |
15 | bc62837b20eb |
hex | 5d0b942d0f77 |
102304312004471 has 2 divisors, whose sum is σ = 102304312004472. Its totient is φ = 102304312004470.
The previous prime is 102304312004399. The next prime is 102304312004519. The reversal of 102304312004471 is 174400213403201.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 102304312004471 - 218 = 102304311742327 is a prime.
It is a super-3 number, since 3×1023043120044713 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (102304312094471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51152156002235 + 51152156002236.
It is an arithmetic number, because the mean of its divisors is an integer number (51152156002236).
Almost surely, 2102304312004471 is an apocalyptic number.
102304312004471 is a deficient number, since it is larger than the sum of its proper divisors (1).
102304312004471 is an equidigital number, since it uses as much as digits as its factorization.
102304312004471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 32.
Adding to 102304312004471 its reverse (174400213403201), we get a palindrome (276704525407672).
The spelling of 102304312004471 in words is "one hundred two trillion, three hundred four billion, three hundred twelve million, four thousand, four hundred seventy-one".
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