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10230443117 is a prime number
BaseRepresentation
bin10011000011100100…
…00010110001101101
3222101222101100122122
421201302002301231
5131422443134432
64411053522325
7511343221526
oct114162026155
928358340578
1010230443117
11437a900374
121b961a33a5
13c7067334b
146d09cb84d
153ed22c612
hex261c82c6d

10230443117 has 2 divisors, whose sum is σ = 10230443118. Its totient is φ = 10230443116.

The previous prime is 10230443089. The next prime is 10230443147. The reversal of 10230443117 is 71134403201.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9351083401 + 879359716 = 96701^2 + 29654^2 .

It is an emirp because it is prime and its reverse (71134403201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10230443117 - 26 = 10230443053 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10230443147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5115221558 + 5115221559.

It is an arithmetic number, because the mean of its divisors is an integer number (5115221559).

Almost surely, 210230443117 is an apocalyptic number.

It is an amenable number.

10230443117 is a deficient number, since it is larger than the sum of its proper divisors (1).

10230443117 is an equidigital number, since it uses as much as digits as its factorization.

10230443117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2016, while the sum is 26.

Adding to 10230443117 its reverse (71134403201), we get a palindrome (81364846318).

The spelling of 10230443117 in words is "ten billion, two hundred thirty million, four hundred forty-three thousand, one hundred seventeen".