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102344324113 is a prime number
BaseRepresentation
bin101111101010000110…
…0100111010000010001
3100210011112220100100201
41133110030213100101
53134100121332423
6115003310015201
710252121254453
oct1372414472021
9323145810321
10102344324113
113a449780549
1217a02aa7501
139860403685
144d4c54a2d3
1529dee642ad
hex17d4327411

102344324113 has 2 divisors, whose sum is σ = 102344324114. Its totient is φ = 102344324112.

The previous prime is 102344324101. The next prime is 102344324219. The reversal of 102344324113 is 311423443201.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 88942325824 + 13401998289 = 298232^2 + 115767^2 .

It is a cyclic number.

It is not a de Polignac number, because 102344324113 - 213 = 102344315921 is a prime.

It is not a weakly prime, because it can be changed into another prime (102344324813) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51172162056 + 51172162057.

It is an arithmetic number, because the mean of its divisors is an integer number (51172162057).

Almost surely, 2102344324113 is an apocalyptic number.

It is an amenable number.

102344324113 is a deficient number, since it is larger than the sum of its proper divisors (1).

102344324113 is an equidigital number, since it uses as much as digits as its factorization.

102344324113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 102344324113 its reverse (311423443201), we get a palindrome (413767767314).

The spelling of 102344324113 in words is "one hundred two billion, three hundred forty-four million, three hundred twenty-four thousand, one hundred thirteen".