Base | Representation |
---|---|
bin | 11101110011010110011… |
… | …11011001000100011011 |
3 | 10121220010102022120000012 |
4 | 32321223033121010123 |
5 | 113234123330212103 |
6 | 2102230400032135 |
7 | 133660465254143 |
oct | 16715317310433 |
9 | 3556112276005 |
10 | 1024001413403 |
11 | 365305114041 |
12 | 14656000264b |
13 | 7574196b2c7 |
14 | 377c1d2d923 |
15 | 1b9839362d8 |
hex | ee6b3d911b |
1024001413403 has 4 divisors (see below), whose sum is σ = 1084236790680. Its totient is φ = 963766036128.
The previous prime is 1024001413399. The next prime is 1024001413417. The reversal of 1024001413403 is 3043141004201.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1024001413403 - 22 = 1024001413399 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1024001413003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30117688613 + ... + 30117688646.
It is an arithmetic number, because the mean of its divisors is an integer number (271059197670).
Almost surely, 21024001413403 is an apocalyptic number.
1024001413403 is a deficient number, since it is larger than the sum of its proper divisors (60235377277).
1024001413403 is an equidigital number, since it uses as much as digits as its factorization.
1024001413403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 60235377276.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 1024001413403 its reverse (3043141004201), we get a palindrome (4067142417604).
The spelling of 1024001413403 in words is "one trillion, twenty-four billion, one million, four hundred thirteen thousand, four hundred three".
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