10240434131 has 4 divisors (see below), whose sum is σ = 10267888752. Its totient is φ = 10212979512.

The previous prime is 10240434101. The next prime is 10240434181. The reversal of 10240434131 is 13143404201.

10240434131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13143404201 = 114377 ⋅114913.

It is a cyclic number.

It is not a de Polignac number, because 10240434131 - 2³⁰ = 9166692307 is a prime.

It is a super-2 number, since 2×10240434131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10240434097 and 10240434106.

It is not an unprimeable number, because it can be changed into a prime (10240434101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13726751 + ... + 13727496.

It is an arithmetic number, because the mean of its divisors is an integer number (2566972188).

Almost surely, 2^10240434131 is an apocalyptic number.

10240434131 is a deficient number, since it is larger than the sum of its proper divisors (27454621).

10240434131 is an equidigital number, since it uses as much as digits as its factorization.

10240434131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27454620.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 10240434131 its reverse (13143404201), we get a palindrome (23383838332).

The spelling of 10240434131 in words is "ten billion, two hundred forty million, four hundred thirty-four thousand, one hundred thirty-one".