Base | Representation |
---|---|
bin | 1001010100001000001100… |
… | …0100110100101000100111 |
3 | 1100021001211212000101201001 |
4 | 2111002003010310220213 |
5 | 2320243342141110002 |
6 | 33440500144414131 |
7 | 2104626316062112 |
oct | 225020304645047 |
9 | 40231755011631 |
10 | 10241401113127 |
11 | 3299398a32298 |
12 | 1194a28617347 |
13 | 5939b58a8272 |
14 | 2759878dd579 |
15 | 12b607db3a87 |
hex | 95083134a27 |
10241401113127 has 2 divisors, whose sum is σ = 10241401113128. Its totient is φ = 10241401113126.
The previous prime is 10241401113113. The next prime is 10241401113227. The reversal of 10241401113127 is 72131110414201.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10241401113127 - 215 = 10241401080359 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10241401113095 and 10241401113104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10241401113227) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5120700556563 + 5120700556564.
It is an arithmetic number, because the mean of its divisors is an integer number (5120700556564).
Almost surely, 210241401113127 is an apocalyptic number.
10241401113127 is a deficient number, since it is larger than the sum of its proper divisors (1).
10241401113127 is an equidigital number, since it uses as much as digits as its factorization.
10241401113127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 28.
Adding to 10241401113127 its reverse (72131110414201), we get a palindrome (82372511527328).
The spelling of 10241401113127 in words is "ten trillion, two hundred forty-one billion, four hundred one million, one hundred thirteen thousand, one hundred twenty-seven".
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