Base | Representation |
---|---|
bin | 10011000101000111… |
… | …00110001010010111 |
3 | 222102212211022120112 |
4 | 21202203212022113 |
5 | 131434304324421 |
6 | 4412240153235 |
7 | 511561513322 |
oct | 114243461227 |
9 | 28385738515 |
10 | 10243433111 |
11 | 43871729aa |
12 | 1b9a60881b |
13 | c73270b32 |
14 | 6d260d7b9 |
15 | 3ee44645b |
hex | 2628e6297 |
10243433111 has 8 divisors (see below), whose sum is σ = 10700926080. Its totient is φ = 9786950712.
The previous prime is 10243433063. The next prime is 10243433171. The reversal of 10243433111 is 11133434201.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 10243433111 - 26 = 10243433047 is a prime.
It is a super-2 number, since 2×102434331112 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (23).
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10243433171) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 231881 + ... + 272498.
It is an arithmetic number, because the mean of its divisors is an integer number (1337615760).
Almost surely, 210243433111 is an apocalyptic number.
10243433111 is a deficient number, since it is larger than the sum of its proper divisors (457492969).
10243433111 is an equidigital number, since it uses as much as digits as its factorization.
10243433111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 505285.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 10243433111 its reverse (11133434201), we get a palindrome (21376867312).
The spelling of 10243433111 in words is "ten billion, two hundred forty-three million, four hundred thirty-three thousand, one hundred eleven".
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