Base | Representation |
---|---|
bin | 1001010100010111001101… |
… | …0101010111010000000111 |
3 | 1100021110020202210201000002 |
4 | 2111011303111113100013 |
5 | 2320330121041343223 |
6 | 33442404140111515 |
7 | 2105131232640506 |
oct | 225056325272007 |
9 | 40243222721002 |
10 | 10245431981063 |
11 | 32a007728a004 |
12 | 119577253559b |
13 | 5941a8a16a16 |
14 | 275c4adaa83d |
15 | 12b791bd4e28 |
hex | 95173557407 |
10245431981063 has 2 divisors, whose sum is σ = 10245431981064. Its totient is φ = 10245431981062.
The previous prime is 10245431981011. The next prime is 10245431981089. The reversal of 10245431981063 is 36018913454201.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10245431981063 - 28 = 10245431980807 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10245431980999 and 10245431981017.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10245431981263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5122715990531 + 5122715990532.
It is an arithmetic number, because the mean of its divisors is an integer number (5122715990532).
Almost surely, 210245431981063 is an apocalyptic number.
10245431981063 is a deficient number, since it is larger than the sum of its proper divisors (1).
10245431981063 is an equidigital number, since it uses as much as digits as its factorization.
10245431981063 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 622080, while the sum is 47.
The spelling of 10245431981063 in words is "ten trillion, two hundred forty-five billion, four hundred thirty-one million, nine hundred eighty-one thousand, sixty-three".
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