Base | Representation |
---|---|
bin | 10011000110011011… |
… | …00011101101101111 |
3 | 222110122112011202211 |
4 | 21203031203231233 |
5 | 132000113330020 |
6 | 4413312031251 |
7 | 512054146342 |
oct | 114315435557 |
9 | 28418464684 |
10 | 10254433135 |
11 | 43923a6431 |
12 | 1ba2232527 |
13 | c7562291b |
14 | 6d3c74459 |
15 | 4003ba85a |
hex | 263363b6f |
10254433135 has 4 divisors (see below), whose sum is σ = 12305319768. Its totient is φ = 8203546504.
The previous prime is 10254433093. The next prime is 10254433139. The reversal of 10254433135 is 53133445201.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 10254433135 - 215 = 10254400367 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 10254433097 and 10254433106.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10254433139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1025443309 + ... + 1025443318.
It is an arithmetic number, because the mean of its divisors is an integer number (3076329942).
Almost surely, 210254433135 is an apocalyptic number.
10254433135 is a deficient number, since it is larger than the sum of its proper divisors (2050886633).
10254433135 is an equidigital number, since it uses as much as digits as its factorization.
10254433135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2050886632.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 10254433135 its reverse (53133445201), we get a palindrome (63387878336).
The spelling of 10254433135 in words is "ten billion, two hundred fifty-four million, four hundred thirty-three thousand, one hundred thirty-five".
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