Base | Representation |
---|---|
bin | 101111110000101001… |
… | …1000010011001101111 |
3 | 100210201212110201122012 |
4 | 1133201103002121233 |
5 | 3140022403040413 |
6 | 115041200511435 |
7 | 10260430365434 |
oct | 1374123023157 |
9 | 323655421565 |
10 | 102564111983 |
11 | 3a551849413 |
12 | 17a6461b57b |
13 | 9896ac8678 |
14 | 4d6d7ddb8b |
15 | 2a043cb7a8 |
hex | 17e14c266f |
102564111983 has 4 divisors (see below), whose sum is σ = 107962223160. Its totient is φ = 97166000808.
The previous prime is 102564111977. The next prime is 102564112061. The reversal of 102564111983 is 389111465201.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 102564111983 - 24 = 102564111967 is a prime.
It is a super-2 number, since 2×1025641119832 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 102564111983.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (102564111943) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2699055560 + ... + 2699055597.
It is an arithmetic number, because the mean of its divisors is an integer number (26990555790).
Almost surely, 2102564111983 is an apocalyptic number.
102564111983 is a deficient number, since it is larger than the sum of its proper divisors (5398111177).
102564111983 is an equidigital number, since it uses as much as digits as its factorization.
102564111983 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5398111176.
The product of its (nonzero) digits is 51840, while the sum is 41.
The spelling of 102564111983 in words is "one hundred two billion, five hundred sixty-four million, one hundred eleven thousand, nine hundred eighty-three".
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