Base | Representation |
---|---|
bin | 11101111110101110111… |
… | …01011011100010001111 |
3 | 10122110220021110112011121 |
4 | 32333113131123202033 |
5 | 113334132133001033 |
6 | 2105121003101411 |
7 | 134265064346632 |
oct | 16772735334217 |
9 | 3573807415147 |
10 | 1030112000143 |
11 | 367960407326 |
12 | 147786511867 |
13 | 761a69164c5 |
14 | 37c016c7c19 |
15 | 1bbe011562d |
hex | efd775b88f |
1030112000143 has 4 divisors (see below), whose sum is σ = 1030151778768. Its totient is φ = 1030072221520.
The previous prime is 1030112000063. The next prime is 1030112000147. The reversal of 1030112000143 is 3410002110301.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1030112000143 is a prime.
It is a super-2 number, since 2×10301120001432 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1030112000147) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19850443 + ... + 19902268.
It is an arithmetic number, because the mean of its divisors is an integer number (257537944692).
Almost surely, 21030112000143 is an apocalyptic number.
1030112000143 is a deficient number, since it is larger than the sum of its proper divisors (39778625).
1030112000143 is an equidigital number, since it uses as much as digits as its factorization.
1030112000143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 39778624.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 1030112000143 its reverse (3410002110301), we get a palindrome (4440114110444).
The spelling of 1030112000143 in words is "one trillion, thirty billion, one hundred twelve million, one hundred forty-three", and thus it is an aban number.
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