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1030112000143 = 2591339752711
BaseRepresentation
bin11101111110101110111…
…01011011100010001111
310122110220021110112011121
432333113131123202033
5113334132133001033
62105121003101411
7134265064346632
oct16772735334217
93573807415147
101030112000143
11367960407326
12147786511867
13761a69164c5
1437c016c7c19
151bbe011562d
hexefd775b88f

1030112000143 has 4 divisors (see below), whose sum is σ = 1030151778768. Its totient is φ = 1030072221520.

The previous prime is 1030112000063. The next prime is 1030112000147. The reversal of 1030112000143 is 3410002110301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1030112000143 is a prime.

It is a super-2 number, since 2×10301120001432 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1030112000147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19850443 + ... + 19902268.

It is an arithmetic number, because the mean of its divisors is an integer number (257537944692).

Almost surely, 21030112000143 is an apocalyptic number.

1030112000143 is a deficient number, since it is larger than the sum of its proper divisors (39778625).

1030112000143 is an equidigital number, since it uses as much as digits as its factorization.

1030112000143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 39778624.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 1030112000143 its reverse (3410002110301), we get a palindrome (4440114110444).

The spelling of 1030112000143 in words is "one trillion, thirty billion, one hundred twelve million, one hundred forty-three", and thus it is an aban number.

Divisors: 1 25913 39752711 1030112000143