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10302111103 = 81112702973
BaseRepresentation
bin10011001100000110…
…11011110101111111
3222120222020110122111
421212003123311333
5132044320023403
64422133554451
7513203333224
oct114603336577
928528213574
1010302111103
114407300609
121bb61a5a27
13c8247713b
146da32594b
1540468756d
hex2660dbd7f

10302111103 has 4 divisors (see below), whose sum is σ = 10314814888. Its totient is φ = 10289407320.

The previous prime is 10302111101. The next prime is 10302111133. The reversal of 10302111103 is 30111120301.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30111120301 = 94811317591.

It is a cyclic number.

It is not a de Polignac number, because 10302111103 - 21 = 10302111101 is a prime.

It is a super-2 number, since 2×103021111032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10302111101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6350676 + ... + 6352297.

It is an arithmetic number, because the mean of its divisors is an integer number (2578703722).

Almost surely, 210302111103 is an apocalyptic number.

10302111103 is a deficient number, since it is larger than the sum of its proper divisors (12703785).

10302111103 is an equidigital number, since it uses as much as digits as its factorization.

10302111103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12703784.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 10302111103 its reverse (30111120301), we get a palindrome (40413231404).

The spelling of 10302111103 in words is "ten billion, three hundred two million, one hundred eleven thousand, one hundred three".

Divisors: 1 811 12702973 10302111103