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103021132147 is a prime number
BaseRepresentation
bin101111111110010001…
…0011011100101110011
3100211220201102202102221
41133330202123211303
53141441402212042
6115154404221511
710304650113643
oct1377442334563
9324821382387
10103021132147
113a76681a42a
1217b7169a897
13993a6b27bb
144db43a8523
152a2e5a4d67
hex17fc89b973

103021132147 has 2 divisors, whose sum is σ = 103021132148. Its totient is φ = 103021132146.

The previous prime is 103021132141. The next prime is 103021132153. The reversal of 103021132147 is 741231120301.

It is a balanced prime because it is at equal distance from previous prime (103021132141) and next prime (103021132153).

It is a cyclic number.

It is not a de Polignac number, because 103021132147 - 223 = 103012743539 is a prime.

It is a super-2 number, since 2×1030211321472 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (103021132141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51510566073 + 51510566074.

It is an arithmetic number, because the mean of its divisors is an integer number (51510566074).

Almost surely, 2103021132147 is an apocalyptic number.

103021132147 is a deficient number, since it is larger than the sum of its proper divisors (1).

103021132147 is an equidigital number, since it uses as much as digits as its factorization.

103021132147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 103021132147 its reverse (741231120301), we get a palindrome (844252252448).

The spelling of 103021132147 in words is "one hundred three billion, twenty-one million, one hundred thirty-two thousand, one hundred forty-seven".