103021300 has 18 divisors (see below), whose sum is σ = 223556438. Its totient is φ = 41208480.

The previous prime is 103021291. The next prime is 103021307. The reversal of 103021300 is 3120301.

103021300 is digitally balanced in base 9, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 3 ways, for example, as 4177936 + 98843364 = 2044^2 + 9942^2 .

It is a super-2 number, since 2×103021300² = 21226776507380000, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (10).

103021300 is strictly pandigital in base 9.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103021307) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 515007 + ... + 515206.

Almost surely, 2^103021300 is an apocalyptic number.

103021300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

103021300 is an abundant number, since it is smaller than the sum of its proper divisors (120535138).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

103021300 is a wasteful number, since it uses less digits than its factorization.

103021300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1030227 (or 1030220 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 10.

The square root of 103021300 is about 10149.9408865274. The cubic root of 103021300 is about 468.7871247634.

Adding to 103021300 its reverse (3120301), we get a palindrome (106141601).

Subtracting from 103021300 its reverse (3120301), we obtain a palindrome (99900999).

The spelling of 103021300 in words is "one hundred three million, twenty-one thousand, three hundred".