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103022031211417 is a prime number
BaseRepresentation
bin10111011011001010101111…
…100100110000101110011001
3111111202210212111012022020001
4113123022233210300232121
5102000403104442231132
61003035400123333001
730462044654460403
oct2733125744605631
9444683774168201
10103022031211417
112a90a44192709a
12b67a439981161
134563c22105306
141b62415a91b73
15bd9c8d259ce7
hex5db2af930b99

103022031211417 has 2 divisors, whose sum is σ = 103022031211418. Its totient is φ = 103022031211416.

The previous prime is 103022031211279. The next prime is 103022031211427. The reversal of 103022031211417 is 714112130220301.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100112751764496 + 2909279446921 = 10005636^2 + 1705661^2 .

It is a cyclic number.

It is not a de Polignac number, because 103022031211417 - 211 = 103022031209369 is a prime.

It is a super-2 number, since 2×1030220312114172 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (103022031211427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51511015605708 + 51511015605709.

It is an arithmetic number, because the mean of its divisors is an integer number (51511015605709).

Almost surely, 2103022031211417 is an apocalyptic number.

It is an amenable number.

103022031211417 is a deficient number, since it is larger than the sum of its proper divisors (1).

103022031211417 is an equidigital number, since it uses as much as digits as its factorization.

103022031211417 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 28.

Adding to 103022031211417 its reverse (714112130220301), we get a palindrome (817134161431718).

The spelling of 103022031211417 in words is "one hundred three trillion, twenty-two billion, thirty-one million, two hundred eleven thousand, four hundred seventeen".