103025403453941 has 2 divisors, whose sum is σ = 103025403453942. Its totient is φ = 103025403453940.

The previous prime is 103025403453883. The next prime is 103025403453943. The reversal of 103025403453941 is 149354304520301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 51549743434225 + 51475660019716 = 7179815^2 + 7174654^2 .

It is a cyclic number.

It is not a de Polignac number, because 103025403453941 - 2⁶ = 103025403453877 is a prime.

It is a super-2 number, since 2×103025403453941² (a number of 29 digits) contains 22 as substring.

Together with 103025403453943, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 103025403453892 and 103025403453901.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (103025403453943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51512701726970 + 51512701726971.

It is an arithmetic number, because the mean of its divisors is an integer number (51512701726971).

Almost surely, 2^{103025403453941} is an apocalyptic number.

It is an amenable number.

103025403453941 is a deficient number, since it is larger than the sum of its proper divisors (1).

103025403453941 is an equidigital number, since it uses as much as digits as its factorization.

103025403453941 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 777600, while the sum is 44.

The spelling of 103025403453941 in words is "one hundred three trillion, twenty-five billion, four hundred three million, four hundred fifty-three thousand, nine hundred forty-one".