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10303112143 is a prime number
BaseRepresentation
bin10011001100001110…
…10000001111001111
3222121001010022211001
421212013100033033
5132100044042033
64422211241131
7513215002552
oct114607201717
928531108731
1010303112143
114407924715
121bb65a91a7
13c8273797c
146da506699
154047d3e7d
hex2661d03cf

10303112143 has 2 divisors, whose sum is σ = 10303112144. Its totient is φ = 10303112142.

The previous prime is 10303112129. The next prime is 10303112153. The reversal of 10303112143 is 34121130301.

10303112143 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10303112143 - 29 = 10303111631 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10303112143.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10303112153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5151556071 + 5151556072.

It is an arithmetic number, because the mean of its divisors is an integer number (5151556072).

Almost surely, 210303112143 is an apocalyptic number.

10303112143 is a deficient number, since it is larger than the sum of its proper divisors (1).

10303112143 is an equidigital number, since it uses as much as digits as its factorization.

10303112143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 10303112143 its reverse (34121130301), we get a palindrome (44424242444).

The spelling of 10303112143 in words is "ten billion, three hundred three million, one hundred twelve thousand, one hundred forty-three".