Search a number
-
+
103031213033102 = 251515606516551
BaseRepresentation
bin10111011011010011010010…
…110110101000011010001110
3111111210200120101102011200212
4113123103102312220122032
5102001030411014024402
61003043515201522422
730462521335615004
oct2733232266503216
9444720511364625
10103031213033102
112a913323814682
12b680180943412
134564a564466b3
141b62a472b6a74
15bda12939e952
hex5db4d2da868e

103031213033102 has 4 divisors (see below), whose sum is σ = 154546819549656. Its totient is φ = 51515606516550.

The previous prime is 103031213033087. The next prime is 103031213033117. The reversal of 103031213033102 is 201330312130301.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (103031213033087) and next prime (103031213033117).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25757803258274 + ... + 25757803258277.

It is an arithmetic number, because the mean of its divisors is an integer number (38636704887414).

Almost surely, 2103031213033102 is an apocalyptic number.

103031213033102 is a deficient number, since it is larger than the sum of its proper divisors (51515606516554).

103031213033102 is an equidigital number, since it uses as much as digits as its factorization.

103031213033102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51515606516553.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 103031213033102 its reverse (201330312130301), we get a palindrome (304361525163403).

The spelling of 103031213033102 in words is "one hundred three trillion, thirty-one billion, two hundred thirteen million, thirty-three thousand, one hundred two".

Divisors: 1 2 51515606516551 103031213033102