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10303130105 = 58419244759
BaseRepresentation
bin10011001100001110…
…10100100111111001
3222121001011020110022
421212013110213321
5132100100130410
64422211500225
7513215106122
oct114607244771
928531136408
1010303130105
114407937164
121bb65b7675
13c82742bb8
146da50d049
154047d9455
hex2661d49f9

10303130105 has 8 divisors (see below), whose sum is σ = 12365275200. Its totient is φ = 8241491376.

The previous prime is 10303130083. The next prime is 10303130107. The reversal of 10303130105 is 50103130301.

10303130105 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10303130105 is a prime.

It is a super-2 number, since 2×103031301052 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (10303130107) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 80285 + ... + 164474.

It is an arithmetic number, because the mean of its divisors is an integer number (1545659400).

Almost surely, 210303130105 is an apocalyptic number.

It is an amenable number.

10303130105 is a deficient number, since it is larger than the sum of its proper divisors (2062145095).

10303130105 is an equidigital number, since it uses as much as digits as its factorization.

10303130105 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 253183.

The product of its (nonzero) digits is 135, while the sum is 17.

Adding to 10303130105 its reverse (50103130301), we get a palindrome (60406260406).

The spelling of 10303130105 in words is "ten billion, three hundred three million, one hundred thirty thousand, one hundred five".

Divisors: 1 5 8419 42095 244759 1223795 2060626021 10303130105