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10304413129 is a prime number
BaseRepresentation
bin10011001100011000…
…01101110111001001
3222121010120102102201
421212030031313021
5132100412210004
64422255200201
7513232031533
oct114614156711
928533512381
1010304413129
11440863310a
121bb6b16061
13c82aa1b9a
146da764853
1540498e6a4
hex26630ddc9

10304413129 has 2 divisors, whose sum is σ = 10304413130. Its totient is φ = 10304413128.

The previous prime is 10304413123. The next prime is 10304413153. The reversal of 10304413129 is 92131440301.

10304413129 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7370565904 + 2933847225 = 85852^2 + 54165^2 .

It is a cyclic number.

It is not a de Polignac number, because 10304413129 - 27 = 10304413001 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10304413097 and 10304413106.

It is not a weakly prime, because it can be changed into another prime (10304413123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5152206564 + 5152206565.

It is an arithmetic number, because the mean of its divisors is an integer number (5152206565).

Almost surely, 210304413129 is an apocalyptic number.

It is an amenable number.

10304413129 is a deficient number, since it is larger than the sum of its proper divisors (1).

10304413129 is an equidigital number, since it uses as much as digits as its factorization.

10304413129 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 28.

The spelling of 10304413129 in words is "ten billion, three hundred four million, four hundred thirteen thousand, one hundred twenty-nine".