10304413153 has 2 divisors, whose sum is σ = 10304413154. Its totient is φ = 10304413152.

The previous prime is 10304413129. The next prime is 10304413157. The reversal of 10304413153 is 35131440301.

10304413153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5940093184 + 4364319969 = 77072^2 + 66063^2 .

It is an emirp because it is prime and its reverse (35131440301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10304413153 - 2⁹ = 10304412641 is a prime.

It is not a weakly prime, because it can be changed into another prime (10304413157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5152206576 + 5152206577.

It is an arithmetic number, because the mean of its divisors is an integer number (5152206577).

Almost surely, 2^10304413153 is an apocalyptic number.

It is an amenable number.

10304413153 is a deficient number, since it is larger than the sum of its proper divisors (1).

10304413153 is an equidigital number, since it uses as much as digits as its factorization.

10304413153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 10304413153 its reverse (35131440301), we get a palindrome (45435853454).

The spelling of 10304413153 in words is "ten billion, three hundred four million, four hundred thirteen thousand, one hundred fifty-three".