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10305433136 = 24644089571
BaseRepresentation
bin10011001100100000…
…00110111000110000
3222121012111020121202
421212100012320300
5132101142330021
64422333110332
7513243510365
oct114620067060
928535436552
1010305433136
11440916a499
121bb73283a8
13c8306b23b
146da94c46c
15404ae1a0b
hex266406e30

10305433136 has 10 divisors (see below), whose sum is σ = 19966776732. Its totient is φ = 5152716560.

The previous prime is 10305433121. The next prime is 10305433139. The reversal of 10305433136 is 63133450301.

It is a super-3 number, since 3×103054331363 (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10305433099 and 10305433108.

It is not an unprimeable number, because it can be changed into a prime (10305433139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 322044770 + ... + 322044801.

Almost surely, 210305433136 is an apocalyptic number.

10305433136 is a gapful number since it is divisible by the number (16) formed by its first and last digit.

It is an amenable number.

10305433136 is a deficient number, since it is larger than the sum of its proper divisors (9661343596).

10305433136 is an equidigital number, since it uses as much as digits as its factorization.

10305433136 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 644089579 (or 644089573 counting only the distinct ones).

The product of its (nonzero) digits is 9720, while the sum is 29.

Adding to 10305433136 its reverse (63133450301), we get a palindrome (73438883437).

The spelling of 10305433136 in words is "ten billion, three hundred five million, four hundred thirty-three thousand, one hundred thirty-six".

Divisors: 1 2 4 8 16 644089571 1288179142 2576358284 5152716568 10305433136