10310030121113 has 4 divisors (see below), whose sum is σ = 10333303327248. Its totient is φ = 10286756914980.

The previous prime is 10310030121103. The next prime is 10310030121133. The reversal of 10310030121113 is 31112103001301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10310030121113 - 2²⁴ = 10310013343897 is a prime.

It is a super-4 number, since 4×10310030121113⁴ (a number of 53 digits) contains 4444 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10310030121091 and 10310030121100.

It is not an unprimeable number, because it can be changed into a prime (10310030121103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11636602403 + ... + 11636603288.

It is an arithmetic number, because the mean of its divisors is an integer number (2583325831812).

Almost surely, 2^{10310030121113} is an apocalyptic number.

It is an amenable number.

10310030121113 is a deficient number, since it is larger than the sum of its proper divisors (23273206135).

10310030121113 is an equidigital number, since it uses as much as digits as its factorization.

10310030121113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23273206134.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 10310030121113 its reverse (31112103001301), we get a palindrome (41422133122414).

The spelling of 10310030121113 in words is "ten trillion, three hundred ten billion, thirty million, one hundred twenty-one thousand, one hundred thirteen".