10310142113 has 2 divisors, whose sum is σ = 10310142114. Its totient is φ = 10310142112.

The previous prime is 10310142109. The next prime is 10310142151. The reversal of 10310142113 is 31124101301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5614055329 + 4696086784 = 74927^2 + 68528^2 .

It is an emirp because it is prime and its reverse (31124101301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10310142113 - 2² = 10310142109 is a prime.

It is a super-2 number, since 2×10310142113² (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10310142091 and 10310142100.

It is not a weakly prime, because it can be changed into another prime (10310142413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5155071056 + 5155071057.

It is an arithmetic number, because the mean of its divisors is an integer number (5155071057).

Almost surely, 2^10310142113 is an apocalyptic number.

It is an amenable number.

10310142113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10310142113 is an equidigital number, since it uses as much as digits as its factorization.

10310142113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 10310142113 its reverse (31124101301), we get a palindrome (41434243414).

The spelling of 10310142113 in words is "ten billion, three hundred ten million, one hundred forty-two thousand, one hundred thirteen".