103102100113 has 2 divisors, whose sum is σ = 103102100114. Its totient is φ = 103102100112.

The previous prime is 103102100111. The next prime is 103102100237. The reversal of 103102100113 is 311001201301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 93860738689 + 9241361424 = 306367^2 + 96132^2 .

It is a cyclic number.

It is not a de Polignac number, because 103102100113 - 2¹ = 103102100111 is a prime.

It is a super-2 number, since 2×103102100113² (a number of 23 digits) contains 22 as substring.

Together with 103102100111, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 103102100093 and 103102100102.

It is not a weakly prime, because it can be changed into another prime (103102100111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51551050056 + 51551050057.

It is an arithmetic number, because the mean of its divisors is an integer number (51551050057).

Almost surely, 2^103102100113 is an apocalyptic number.

It is an amenable number.

103102100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

103102100113 is an equidigital number, since it uses as much as digits as its factorization.

103102100113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 103102100113 its reverse (311001201301), we get a palindrome (414103301414).

The spelling of 103102100113 in words is "one hundred three billion, one hundred two million, one hundred thousand, one hundred thirteen".