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1031030112013 = 1193730010183
BaseRepresentation
bin11110000000011100010…
…11101111111100001101
310122120021021001102212221
433000032023233330031
5113343022202041023
62105352041255341
7134326613231626
oct17001613577415
93576237042787
101031030112013
1136829168a370
121479a1a94551
13762c1bb1a75
1437c8b5daa4d
151bc45a1d85d
hexf00e2eff0d

1031030112013 has 4 divisors (see below), whose sum is σ = 1124760122208. Its totient is φ = 937300101820.

The previous prime is 1031030111999. The next prime is 1031030112067. The reversal of 1031030112013 is 3102110301301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1031030112013 - 229 = 1030493241101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1031030112713) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46865005081 + ... + 46865005102.

It is an arithmetic number, because the mean of its divisors is an integer number (281190030552).

Almost surely, 21031030112013 is an apocalyptic number.

It is an amenable number.

1031030112013 is a deficient number, since it is larger than the sum of its proper divisors (93730010195).

1031030112013 is an equidigital number, since it uses as much as digits as its factorization.

1031030112013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 93730010194.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1031030112013 its reverse (3102110301301), we get a palindrome (4133140413314).

The spelling of 1031030112013 in words is "one trillion, thirty-one billion, thirty million, one hundred twelve thousand, thirteen".

Divisors: 1 11 93730010183 1031030112013