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103110132103 = 119373648373
BaseRepresentation
bin110000000000111010…
…1111100000110000111
3100212010220220102102121
41200001311330012013
53142132143211403
6115211303550411
710310110443016
oct1400165740607
9325126812377
10103110132103
113a801a88410
1217b9745b407
139952c744b4
144dc2134a7d
152a372d53bd
hex1801d7c187

103110132103 has 4 divisors (see below), whose sum is σ = 112483780488. Its totient is φ = 93736483720.

The previous prime is 103110132061. The next prime is 103110132109. The reversal of 103110132103 is 301231011301.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 103110132103 - 225 = 103076577671 is a prime.

It is a super-2 number, since 2×1031101321032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103110132109) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4686824176 + ... + 4686824197.

It is an arithmetic number, because the mean of its divisors is an integer number (28120945122).

Almost surely, 2103110132103 is an apocalyptic number.

103110132103 is a deficient number, since it is larger than the sum of its proper divisors (9373648385).

103110132103 is an equidigital number, since it uses as much as digits as its factorization.

103110132103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9373648384.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 103110132103 its reverse (301231011301), we get a palindrome (404341143404).

The spelling of 103110132103 in words is "one hundred three billion, one hundred ten million, one hundred thirty-two thousand, one hundred three".

Divisors: 1 11 9373648373 103110132103