Base | Representation |
---|---|
bin | 10111011100011101110011… |
… | …101101111111001010010110 |
3 | 111112002100002022002202121101 |
4 | 113130131303231333022112 |
5 | 102003333240123410402 |
6 | 1003144350252540314 |
7 | 30501353121011545 |
oct | 2734356355771226 |
9 | 445070068082541 |
10 | 103111221310102 |
11 | 2a944250364355 |
12 | b69378b48169a |
13 | 456c4671b8a35 |
14 | 1b668771a815c |
15 | bdc25d455b87 |
hex | 5dc773b7f296 |
103111221310102 has 4 divisors (see below), whose sum is σ = 154666831965156. Its totient is φ = 51555610655050.
The previous prime is 103111221309961. The next prime is 103111221310103. The reversal of 103111221310102 is 201013122111301.
It is a semiprime because it is the product of two primes.
It is a self number, because there is not a number n which added to its sum of digits gives 103111221310102.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (103111221310103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25777805327524 + ... + 25777805327527.
It is an arithmetic number, because the mean of its divisors is an integer number (38666707991289).
Almost surely, 2103111221310102 is an apocalyptic number.
103111221310102 is a deficient number, since it is larger than the sum of its proper divisors (51555610655054).
103111221310102 is an equidigital number, since it uses as much as digits as its factorization.
103111221310102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51555610655053.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 103111221310102 its reverse (201013122111301), we get a palindrome (304124343421403).
The spelling of 103111221310102 in words is "one hundred three trillion, one hundred eleven billion, two hundred twenty-one million, three hundred ten thousand, one hundred two".
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