Base | Representation |
---|---|
bin | 10011001101001100… |
… | …10001100011011101 |
3 | 222121121102110121211 |
4 | 21212212101203131 |
5 | 132104134301442 |
6 | 4423101424421 |
7 | 513344061565 |
oct | 114646214335 |
9 | 28547373554 |
10 | 10311243997 |
11 | 441147925a |
12 | 1bb926b111 |
13 | c84324112 |
14 | 6db621da5 |
15 | 40538d617 |
hex | 2669918dd |
10311243997 has 2 divisors, whose sum is σ = 10311243998. Its totient is φ = 10311243996.
The previous prime is 10311243977. The next prime is 10311244001. The reversal of 10311243997 is 79934211301.
10311243997 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9287947876 + 1023296121 = 96374^2 + 31989^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10311243997 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10311243907) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5155621998 + 5155621999.
It is an arithmetic number, because the mean of its divisors is an integer number (5155621999).
Almost surely, 210311243997 is an apocalyptic number.
It is an amenable number.
10311243997 is a deficient number, since it is larger than the sum of its proper divisors (1).
10311243997 is an equidigital number, since it uses as much as digits as its factorization.
10311243997 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40824, while the sum is 40.
The spelling of 10311243997 in words is "ten billion, three hundred eleven million, two hundred forty-three thousand, nine hundred ninety-seven".
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