Base | Representation |
---|---|
bin | 110000000001000000… |
… | …1010000101110101001 |
3 | 100212011010111012220011 |
4 | 1200002001100232221 |
5 | 3142133423201301 |
6 | 115211451331521 |
7 | 10310144614246 |
oct | 1400201205651 |
9 | 325133435804 |
10 | 103113100201 |
11 | 3a803725391 |
12 | 17b98450ba1 |
13 | 9953773477 |
14 | 4dc26a85cd |
15 | 2a376bea51 |
hex | 1802050ba9 |
103113100201 has 2 divisors, whose sum is σ = 103113100202. Its totient is φ = 103113100200.
The previous prime is 103113100199. The next prime is 103113100217. The reversal of 103113100201 is 102001311301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 63948294400 + 39164805801 = 252880^2 + 197901^2 .
It is a cyclic number.
It is not a de Polignac number, because 103113100201 - 21 = 103113100199 is a prime.
It is a super-2 number, since 2×1031131002012 (a number of 23 digits) contains 22 as substring.
Together with 103113100199, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (103113100291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51556550100 + 51556550101.
It is an arithmetic number, because the mean of its divisors is an integer number (51556550101).
Almost surely, 2103113100201 is an apocalyptic number.
It is an amenable number.
103113100201 is a deficient number, since it is larger than the sum of its proper divisors (1).
103113100201 is an equidigital number, since it uses as much as digits as its factorization.
103113100201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 103113100201 its reverse (102001311301), we get a palindrome (205114411502).
The spelling of 103113100201 in words is "one hundred three billion, one hundred thirteen million, one hundred thousand, two hundred one".
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