Base | Representation |
---|---|
bin | 1001011000001100101000… |
… | …0011000100011000011011 |
3 | 1100111202022000101111011012 |
4 | 2112003022003010120123 |
5 | 2322420031143444121 |
6 | 33532541230524135 |
7 | 2112652623006104 |
oct | 226031203043033 |
9 | 40452260344135 |
10 | 10311311312411 |
11 | 331600346979a |
12 | 11a649936664b |
13 | 59a4775405a5 |
14 | 2790da61b3ab |
15 | 12d34a686c5b |
hex | 960ca0c461b |
10311311312411 has 2 divisors, whose sum is σ = 10311311312412. Its totient is φ = 10311311312410.
The previous prime is 10311311312389. The next prime is 10311311312483. The reversal of 10311311312411 is 11421311311301.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10311311312411 is a prime.
It is not a weakly prime, because it can be changed into another prime (10311311312111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5155655656205 + 5155655656206.
It is an arithmetic number, because the mean of its divisors is an integer number (5155655656206).
Almost surely, 210311311312411 is an apocalyptic number.
10311311312411 is a deficient number, since it is larger than the sum of its proper divisors (1).
10311311312411 is an equidigital number, since it uses as much as digits as its factorization.
10311311312411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 23.
Adding to 10311311312411 its reverse (11421311311301), we get a palindrome (21732622623712).
The spelling of 10311311312411 in words is "ten trillion, three hundred eleven billion, three hundred eleven million, three hundred twelve thousand, four hundred eleven".
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