10311313133 has 4 divisors (see below), whose sum is σ = 11248705248. Its totient is φ = 9373921020.

The previous prime is 10311313087. The next prime is 10311313141. The reversal of 10311313133 is 33131311301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10311313133 - 2¹⁸ = 10311050989 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10311313633) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 468696041 + ... + 468696062.

It is an arithmetic number, because the mean of its divisors is an integer number (2812176312).

Almost surely, 2^10311313133 is an apocalyptic number.

It is an amenable number.

10311313133 is a deficient number, since it is larger than the sum of its proper divisors (937392115).

10311313133 is an equidigital number, since it uses as much as digits as its factorization.

10311313133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 937392114.

The product of its (nonzero) digits is 243, while the sum is 20.

Adding to 10311313133 its reverse (33131311301), we get a palindrome (43442624434).

The spelling of 10311313133 in words is "ten billion, three hundred eleven million, three hundred thirteen thousand, one hundred thirty-three".