1031133111013 has 4 divisors (see below), whose sum is σ = 1055112950848. Its totient is φ = 1007153271180.

The previous prime is 1031133110999. The next prime is 1031133111037. The reversal of 1031133111013 is 3101113311301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1031133111013 - 2¹³ = 1031133102821 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1031133111053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11989919853 + ... + 11989919938.

It is an arithmetic number, because the mean of its divisors is an integer number (263778237712).

Almost surely, 2^{1031133111013} is an apocalyptic number.

It is an amenable number.

1031133111013 is a deficient number, since it is larger than the sum of its proper divisors (23979839835).

1031133111013 is an equidigital number, since it uses as much as digits as its factorization.

1031133111013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23979839834.

The product of its (nonzero) digits is 81, while the sum is 19.

Adding to 1031133111013 its reverse (3101113311301), we get a palindrome (4132246422314).

The spelling of 1031133111013 in words is "one trillion, thirty-one billion, one hundred thirty-three million, one hundred eleven thousand, thirteen".