Base | Representation |
---|---|
bin | 10111011100011111110001… |
… | …100101011110111011001010 |
3 | 111112002112112110122020110020 |
4 | 113130133301211132323022 |
5 | 102003402101222310442 |
6 | 1003145340010001310 |
7 | 30501456342115431 |
oct | 2734376145367312 |
9 | 445075473566406 |
10 | 103113333010122 |
11 | 2a945134363886 |
12 | b69407a716236 |
13 | 456c712842186 |
14 | 1b669d781c118 |
15 | bdc333a2e9ec |
hex | 5dc7f195eeca |
103113333010122 has 32 divisors (see below), whose sum is σ = 218902179245184. Its totient is φ = 32268609408000.
The previous prime is 103113333010091. The next prime is 103113333010133. The reversal of 103113333010122 is 221010333311301.
It is a junction number, because it is equal to n+sod(n) for n = 103113333010092 and 103113333010101.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1260451654 + ... + 1260533457.
It is an arithmetic number, because the mean of its divisors is an integer number (6840693101412).
Almost surely, 2103113333010122 is an apocalyptic number.
103113333010122 is an abundant number, since it is smaller than the sum of its proper divisors (115788846235062).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
103113333010122 is a wasteful number, since it uses less digits than its factorization.
103113333010122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2520985534.
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 103113333010122 its reverse (221010333311301), we get a palindrome (324123666321423).
The spelling of 103113333010122 in words is "one hundred three trillion, one hundred thirteen billion, three hundred thirty-three million, ten thousand, one hundred twenty-two".
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